document.write( "Question 633288: 3x - y + 4z = 12
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document.write( "x + y - 3z = -4
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document.write( "4x + y - z = 7 \r
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document.write( "x =
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document.write( "y =
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document.write( "z = \n" );
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Algebra.Com's Answer #398931 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! 3x - y + 4z = 12 \n" ); document.write( "x + y - 3z = -4 \n" ); document.write( "4x + y - z = 7 \n" ); document.write( "-------------------add the three equations, eliminates z \n" ); document.write( "8x + y = 15 \n" ); document.write( ": \n" ); document.write( "Using the 2nd and 3rd equations, multiply the 3rd by -3, add to the 2nd \n" ); document.write( "x + y - 3z = -4 \n" ); document.write( "-12x - 3y + 3z = -21 \n" ); document.write( "-------------------- adding eliminates z \n" ); document.write( "-11x - 2y = -25 \n" ); document.write( "16x + 2y = 30; multiplied 8x+y=15 by 2 \n" ); document.write( "---------------adding eliminates y, find x \n" ); document.write( "5x = 5 \n" ); document.write( "x = 1 \n" ); document.write( ": \n" ); document.write( "Find y \n" ); document.write( "8x + y = 15 \n" ); document.write( "8(1) + y = 15 \n" ); document.write( "y = 15 -8 \n" ); document.write( "y = 7 \n" ); document.write( ": \n" ); document.write( "Find z \n" ); document.write( "3x - y + 4z = 12 \n" ); document.write( "3(1) - 7 + 4z = 12 \n" ); document.write( "-4 + 4z = 12 \n" ); document.write( "4z = 12 + 4 \n" ); document.write( "z = 16/4 \n" ); document.write( "z = 4 \n" ); document.write( ": \n" ); document.write( "Summarize \n" ); document.write( "x = 1 \n" ); document.write( "y = 7 \n" ); document.write( "z = 4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the 2nd equation \n" ); document.write( "x + y - 3z = -4 \n" ); document.write( "1 + 7 - 3(4) = -4 \n" ); document.write( "8 - 12 = -4 \n" ); document.write( ": \n" ); document.write( "You can check this in the other two equations \n" ); document.write( " |