document.write( "Question 58100: The width of a rectangle is 3/4 of its length. If the perimeter of the rectangle is 140 feet, what are the dimensions of the rectangle?\r
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Algebra.Com's Answer #39890 by funmath(2933)\"\" \"About 
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The width of a rectangle is 3/4 of its length. If the perimeter of the rectangle is 140 feet, what are the dimensions of the rectangle?
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\n" ); document.write( "The formula for perimeter of a rectangle is:\"highlight%28P=2L%2B2W%29\"
\n" ); document.write( "Let the length (L) be:x
\n" ); document.write( "Then width (W) is: (3/4)x
\n" ); document.write( "Perimeter (P) is: 140 ft
\n" ); document.write( ": Plug those values into your formula and solve for x:
\n" ); document.write( "140=2(x)+2(3/4)x
\n" ); document.write( "140=2x+6/4x
\n" ); document.write( "140=2x+3/2x
\n" ); document.write( "140=(4/2)x+(3/2)x
\n" ); document.write( "140=(7/2)x
\n" ); document.write( "2(140)=2(7/2)x
\n" ); document.write( "280=7x
\n" ); document.write( "280/7=7x/7
\n" ); document.write( "40=x
\n" ); document.write( "Length: x=40 ft.
\n" ); document.write( "Width:(3/4)(40)=3(10)=30 ft.
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\n" ); document.write( "Happy Calculating!!! \n" ); document.write( "
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