document.write( "Question 633407: a man divides PHP6,500 ampng his children in such a way that the second receives two-thirds as much as the first but; PHP500 more than the third. how much does each receive? \n" ); document.write( "

Algebra.Com's Answer #398878 by Edwin McCravy(20067) $\"\"$ $\"About$

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a man divides PHP6,500 ampng his children in such a way that the second receives two-thirds as much as the first but; PHP500 more than the third. how much does each receive?
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document.write( "x + y + z = 6500\r\n" );
document.write( "        y = x\r\n" );
document.write( "        y = z + 500\r\n" );
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document.write( "Solve the second equation for x\r\n" );
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document.write( "        y = x\r\n" );
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document.write( "Multiply both sides by 3 to clear the fraction\r\n" );
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document.write( "       3y = 2x\r\n" );
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document.write( "Divide both sides by 2\r\n" );
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document.write( "       y = x\r\n" );
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document.write( "Now we have something to substitute for x in terms of y\r\n" );
document.write( "in the first equation. \r\n" );
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document.write( "Now we need something to substitute for z in terms of y\r\n" );
document.write( "in the first equation.  So we solve the third equation\r\n" );
document.write( "for z:\r\n" );
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document.write( "        y = z + 500\r\n" );
document.write( "  y - 500 = z\r\n" );
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document.write( "Now we substitute y for x, and y - 500 for z\r\n" );
document.write( "in the first equation:\r\n" );
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document.write( " x + y + z = 6500\r\n" );
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document.write( "y + y + y - 500 = 6500\r\n" );
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document.write( "Clear the fraction by multiplying through by 2\r\n" );
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document.write( " 3y + 2y + 2y - 1000 = 13000\r\n" );
document.write( "           7y = 14000\r\n" );
document.write( "            y = 2000\r\n" );
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document.write( "   y - 500 = z\r\n" );
document.write( "2000 - 500 = z\r\n" );
document.write( "      1500 = z\r\n" );
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document.write( "       y = x\r\n" );
document.write( "  (2000) = x\r\n" );
document.write( "     3000 = x\r\n" );
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document.write( "The first receives PHP3,000\r\n" );
document.write( "The second receives PHP2,000\r\n" );
document.write( "The third receives PHP1,500\r\n" );
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document.write( "Edwin

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