document.write( "Question 633377: Melissa invested a sum of money at 3% annual interest. She invested three times that sum at 5% annual interest. If her total yearly interest from both investments was 5400, how much was invested at 3% \n" ); document.write( "
Algebra.Com's Answer #398856 by John10(297)\"\" \"About 
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Melissa invested a sum of money at 3% annual interest. She invested three times that sum at 5% annual interest. If her total yearly interest from both investments was 5400, how much was invested at 3% ?\r
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\n" ); document.write( "\n" ); document.write( "Hello, we need to find the sum of money which invest at 3% interest.\r
\n" ); document.write( "\n" ); document.write( "So we will assume that amount is x. Thus the amount of money invest into 5% is 3x.\r
\n" ); document.write( "\n" ); document.write( "We know that the sum of interest from both account (3% and 5%) is 5400.\r
\n" ); document.write( "\n" ); document.write( "We will have an equation:\r
\n" ); document.write( "\n" ); document.write( "0.03x + 0.05(3x) = 5400
\n" ); document.write( "0.03x + 0.15x = 5400
\n" ); document.write( "0.18x = 5400
\n" ); document.write( "x = 5400/0.18
\n" ); document.write( "x = 30,000\r
\n" ); document.write( "\n" ); document.write( "Thus the sum of money invest in 3% is $30,000.\r
\n" ); document.write( "\n" ); document.write( "Hope it helps:)\r
\n" ); document.write( "\n" ); document.write( "John10
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