document.write( "Question 633353: I need help contructing a binomial distribution for n=4, p= 0.05 \n" ); document.write( "
Algebra.Com's Answer #398845 by Edwin McCravy(20086) You can put this solution on YOUR website! \r\n" ); document.write( "n=4, p= 0.05\r\n" ); document.write( "\r\n" ); document.write( " x p(x) = C(5,x)(.05)x(.95)5-x\r\n" ); document.write( "-------------------------------------------------------\r\n" ); document.write( " 0 p(0) = C(5,0)(.05)0(.95)5-0 = .774\r\n" ); document.write( " 1 p(1) = C(5,1)(.05)1(.95)5-1 = .204\r\n" ); document.write( " 2 p(2) = C(5,2)(.05)2(.95)5-2 = .021\r\n" ); document.write( " 3 p(3) = C(5,3)(.05)3(.95)5-3 = .001\r\n" ); document.write( " 4 p(4) = C(5,4)(.05)4(.95)5-4 = .000 \r\n" ); document.write( " 5 p(5) = C(5,5)(.05)5(.95)5-5 = .000\r\n" ); document.write( "\r\n" ); document.write( "Shorten the table to just two columns:\r\n" ); document.write( "\r\n" ); document.write( " x p(x) \r\n" ); document.write( "---------\r\n" ); document.write( " 0 .774\r\n" ); document.write( " 1 .204\r\n" ); document.write( " 2 .021\r\n" ); document.write( " 3 .001\r\n" ); document.write( " 4 .000 \r\n" ); document.write( " 5 .000\r\n" ); document.write( "---------\r\n" ); document.write( "sum=1.000\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |