document.write( "Question 633335: john rowed 12 miles down river took 2 hour but the return trip took 3 hours
\n" );
document.write( "how fast is john going with out the flow of water?\n" );
document.write( "and how fast is the current of water? \n" );
document.write( "
Algebra.Com's Answer #398820 by graphmatics(170)![]() ![]() You can put this solution on YOUR website! Let J be John's speed and let S be the stream's speed. \n" ); document.write( "12/(J+S)=2 \n" ); document.write( "12/(J-S)=3 \n" ); document.write( " \n" ); document.write( "12=2J+2S \n" ); document.write( "\n" ); document.write( "12=3J-3S \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 36=6J+6S \n" ); document.write( "-24=-6J+6S \n" ); document.write( " \n" ); document.write( "12=12S \n" ); document.write( "S=1 \n" ); document.write( "12=2J+2(1) \n" ); document.write( "J=5 \n" ); document.write( "So John's speed is 5mph and the current speed is 1mph. \n" ); document.write( " |