document.write( "Question 633335: john rowed 12 miles down river took 2 hour but the return trip took 3 hours
\n" ); document.write( "how fast is john going with out the flow of water?\n" ); document.write( "and how fast is the current of water?
\n" ); document.write( "

Algebra.Com's Answer #398820 by graphmatics(170)\"\" \"About 
You can put this solution on YOUR website!
Let J be John's speed and let S be the stream's speed.
\n" ); document.write( "12/(J+S)=2
\n" ); document.write( "12/(J-S)=3
\n" ); document.write( "
\n" ); document.write( "12=2J+2S
\n" ); document.write( "\n" ); document.write( "12=3J-3S
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " 36=6J+6S
\n" ); document.write( "-24=-6J+6S
\n" ); document.write( "
\n" ); document.write( "12=12S
\n" ); document.write( "S=1
\n" ); document.write( "12=2J+2(1)
\n" ); document.write( "J=5
\n" ); document.write( "So John's speed is 5mph and the current speed is 1mph.
\n" ); document.write( "
\n" );