document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=633258>Question 633258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A goldsmith has two gold alloys. The first alloy is 30% gold; the second alloy is 80% gold. How many grams of each should be mixed to produce 40 grams of an alloy that is 70% gold?\r<BR>\n" );
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document.write( "Amount of 30% gold in grams?<BR>\n" );
document.write( "Amount of 80% gold in grams?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398819 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A goldsmith has two gold alloys.<BR>\n" );
document.write( " The first alloy is 30% gold; the second alloy is 80% gold.<BR>\n" );
document.write( " How many grams of each should be mixed to produce 40 grams of an alloy<BR>\n" );
document.write( " that is 70% gold?<BR>\n" );
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document.write( "Let x = amt of 80% alloy required<BR>\n" );
document.write( "the resulting total is to be 40 grams, therefore:<BR>\n" );
document.write( "(40-x) = amt of 30% gold<BR>\n" );
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document.write( ".80x + .30(40-x) = .70(40)<BR>\n" );
document.write( ".80x + 12 - .30x = 28<BR>\n" );
document.write( ".80x - .30x = 28 - 12<BR>\n" );
document.write( ".50x = 16<BR>\n" );
document.write( "x = 16/.5<BR>\n" );
document.write( "x = 32 grams of the 80% alloy<BR>\n" );
document.write( "then<BR>\n" );
document.write( "40 - 32 = 8 grams of 30% alloy<BR>\n" );
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