document.write( "Question 633277: Twice last month, Alice rented a car from the same company. She was charged a daily fee, plus an additional charge per mile driven. The first trip lasted 4 days, she drove 380 miles, and the rental cost her $180.20. On her second trip she drove 625 miles in 5 days, and paid $253.75 for the rental. Find the daily fee and the mileage charge. \n" ); document.write( "
Algebra.Com's Answer #398816 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x Rate per mile \n" ); document.write( "y daily charge \n" ); document.write( "Total memberships \n" ); document.write( "180 x + 4 y = 180.20 .............1 \n" ); document.write( " \n" ); document.write( "625 x + 5 y = 253.75 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -5 \n" ); document.write( "Multiply (2) by 4 \n" ); document.write( "-900 x -20 y = -901 \n" ); document.write( "2500 x + 20 y = 1015 \n" ); document.write( "Add the two equations \n" ); document.write( "1600 x = 114 \n" ); document.write( "/ 1600 \n" ); document.write( "x = 0.07 \n" ); document.write( "0.07 *100 = 7 cents/mile \n" ); document.write( "plug value of x in (1) \n" ); document.write( "180 x + 4 y = 180 \n" ); document.write( "13 + 4 y = 180 \n" ); document.write( " 4 y = 180 -13 \n" ); document.write( " 4 y = 167 \n" ); document.write( " y = 42\r \n" ); document.write( "\n" ); document.write( "7 cents per mile & $42 per day \n" ); document.write( " \n" ); document.write( " |