document.write( "Question 633335: john rowed 12 miles down river took 2 hour but the return trip took 3 hours
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document.write( "how fast is john going with out the flow of water?\n" );
document.write( "and how fast is the current of water? \n" );
document.write( "
Algebra.Com's Answer #398815 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed =x mph \n" ); document.write( "current speed =y mph \n" ); document.write( "againstcurrent x-y 3 hours \n" ); document.write( "with current x+y 2 hours \n" ); document.write( " \n" ); document.write( "Distance = 12 miles distance= 12 \n" ); document.write( "t=d/r against current \n" ); document.write( "12.00 / ( x - y )= 3.00 \n" ); document.write( " \n" ); document.write( "3.00 x - -3.00 y = 12.00 ....................1 \n" ); document.write( "downstream \n" ); document.write( "12.00 / ( x + y )= 2.00 \n" ); document.write( "2.00 ( x + y ) = 12.00 \n" ); document.write( "2.00 x + 2.00 y = 12.00 ...............2 \n" ); document.write( "Multiply (1) by 2.00 \n" ); document.write( "Multiply (2) by 3.00 \n" ); document.write( "we get \n" ); document.write( "6.00 x + -6.00 y = 24.00 \n" ); document.write( "6.00 x + 6.00 y = 36.00 \n" ); document.write( "12.00 x = 60.00 \n" ); document.write( "/ 12.00 \n" ); document.write( "x = 5 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) \n" ); document.write( "3 x -3 y = 12 \n" ); document.write( "15 -3 y = 12 \n" ); document.write( "-3 y = 12 -15 \n" ); document.write( "-3 y = -3 \n" ); document.write( " y = 1 mph \n" ); document.write( " Boat 5 mph \n" ); document.write( " current 1 mph \n" ); document.write( " \n" ); document.write( " |