document.write( "Question 633335: john rowed 12 miles down river took 2 hour but the return trip took 3 hours
\n" ); document.write( "how fast is john going with out the flow of water?\n" ); document.write( "and how fast is the current of water?
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Algebra.Com's Answer #398815 by mananth(16946)\"\" \"About 
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Boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "againstcurrent x-y 3 hours
\n" ); document.write( "with current x+y 2 hours
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\n" ); document.write( "Distance = 12 miles distance= 12
\n" ); document.write( "t=d/r against current
\n" ); document.write( "12.00 / ( x - y )= 3.00
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\n" ); document.write( "3.00 x - -3.00 y = 12.00 ....................1
\n" ); document.write( "downstream
\n" ); document.write( "12.00 / ( x + y )= 2.00
\n" ); document.write( "2.00 ( x + y ) = 12.00
\n" ); document.write( "2.00 x + 2.00 y = 12.00 ...............2
\n" ); document.write( "Multiply (1) by 2.00
\n" ); document.write( "Multiply (2) by 3.00
\n" ); document.write( "we get
\n" ); document.write( "6.00 x + -6.00 y = 24.00
\n" ); document.write( "6.00 x + 6.00 y = 36.00
\n" ); document.write( "12.00 x = 60.00
\n" ); document.write( "/ 12.00
\n" ); document.write( "x = 5 mph
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\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3 x -3 y = 12
\n" ); document.write( "15 -3 y = 12
\n" ); document.write( "-3 y = 12 -15
\n" ); document.write( "-3 y = -3
\n" ); document.write( " y = 1 mph
\n" ); document.write( " Boat 5 mph
\n" ); document.write( " current 1 mph
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