document.write( "Question 633328: Given the mean equal to 26 and the standard deviation equal to 3, what is the chance that a value of X greater than 18 will occur? \n" ); document.write( "
Algebra.Com's Answer #398807 by stanbon(75887)\"\" \"About 
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Given the mean equal to 26 and the standard deviation equal to 3, what is the chance that a value of X greater than 18 will occur?
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\n" ); document.write( "z(18) = (18-26)/3 = -8/3
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\n" ); document.write( "P(x > 18) = P(z > -8/3) = normalcdf(-8/3,100) = 0.9962
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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