document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=633315>Question 633315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello I'm a college student in need of help with my elementary algebra problem. And it goes...The length of a rectangle is five times its width. When the length is decreased by 3m and the width is increased by 2m, the area of the new rectangle is 60m^2. Find the original length and width. \r<BR>\n" );
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document.write( "I tried using the A=lw formula but it doesn't make any sense to me. I get stuck...I did 60=(5x-3)(x+2) and I came out 12.6 and that didn't match up. I also tried 60=5x(x) = 60=5x^2 = 5(x^2-12=0 and then I get completely stuck.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398798 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (l-3)*(w+2)=60<BR>\n" );
document.write( "l=5w<BR>\n" );
document.write( "I changed your x to w for width<BR>\n" );
document.write( "Your 60=(5w-3)(w+2) is correct but w=3 not 12.6<BR>\n" );
document.write( "check<BR>\n" );
document.write( "60=(15-3)*(3+2)<BR>\n" );
document.write( "60=12*5<BR>\n" );
document.write( "ok\r<BR>\n" );
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