document.write( "Question 633098: An investment of $25,400 is placed into an account that earns 6.5% interest compounded quarterly. In how many years will the investment be worth twice the original amount?\r
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document.write( "2) Solve: log3(x+8) + log3x=2 The 3 are are at the bottom right corner. \r
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document.write( "3) log5x-log5(5-2)=log5(4) The 5 is in the bottom right corner also \r
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document.write( "4) 2^3x+1=13.4 \n" );
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Algebra.Com's Answer #398750 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An investment of $25,400 is placed into an account that earns 6.5% interest \n" ); document.write( " compounded quarterly. \n" ); document.write( "In how many years will the investment be worth twice the original amount? \n" ); document.write( ": \n" ); document.write( "How long to double, the amt doesn't matter \n" ); document.write( "let t = no. of yrs to double \n" ); document.write( "(1+ \n" ); document.write( " \n" ); document.write( "4t = \n" ); document.write( "4t = 43 \n" ); document.write( "t = 43/4 \n" ); document.write( "t = 10.75 yrs to double in value \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "2) Solve: log3(x+8) + log3(x) = 2 \n" ); document.write( "addition of logs is multiply \n" ); document.write( "log3(x(x+8)) = 2 \n" ); document.write( "exponent of equiv of logs \n" ); document.write( "x(x+8) = 3^2 \n" ); document.write( "x^2 + 8x = 9 \n" ); document.write( "a quadratic equation \n" ); document.write( "x^2 + 8x - 9 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x+9)(x-1) = 0 \n" ); document.write( "only the positive solution can be used here \n" ); document.write( "x = 1 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "3) log5(x) - log5(5-2)= log5(4) \n" ); document.write( "log5(x) - log5(3)= log5(4) \n" ); document.write( "subtraction of log means divide \n" ); document.write( "log5 \n" ); document.write( "eliminate log5 from both sides \n" ); document.write( " \n" ); document.write( "x = 3(4) \n" ); document.write( "x = 12 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "4) 2^3x+1=13.4 \n" ); document.write( "Assume this is \n" ); document.write( " \n" ); document.write( "3x + 1 = \n" ); document.write( "3x + 1 = 3.744 \n" ); document.write( "3x = 3.744 - 1 \n" ); document.write( "3x = 2.744 \n" ); document.write( "x = \n" ); document.write( "x = .9147 \n" ); document.write( "Check this on your calc: enter 2^(3(.9147)+1), results: ~13.4 \n" ); document.write( " |