document.write( "Question 633222: Solve for x
\n" ); document.write( "x+10-2x=15\r
\n" ); document.write( "\n" ); document.write( "solve x^divided by x^=
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Algebra.Com's Answer #398742 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%2B10-2x=15\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-x%2B10=15\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=15-10\" Subtract \"10\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=5\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%285%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=-5\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=-5\" \r
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