document.write( "Question 633211: The sum of three integers is 48. If the first integer is doubled, the sum is 60. If the second integer is doubled, the sum is 63. Find the integers. \n" ); document.write( "
| Algebra.Com's Answer #398733 by flame8855(424)     You can put this solution on YOUR website! x+y+z = 48 \n" ); document.write( "2x+y+z= 60 \n" ); document.write( "x+2y+z = 63 \n" ); document.write( "solve\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+z = 48-y\r \n" ); document.write( "\n" ); document.write( "x+z = 63-2y \n" ); document.write( "48-y = 63 -2y \n" ); document.write( "y = 63-48 = 15 \n" ); document.write( "x+y= 48-15 \n" ); document.write( "x+y = 33 \n" ); document.write( "2x+y= 45 \n" ); document.write( "33-x= 45-2x \n" ); document.write( "x= 12 \n" ); document.write( "x+y+z = 48 \n" ); document.write( "z= 48 - 12- 15 \n" ); document.write( "z = 21 \n" ); document.write( "so 12 , 15 , 21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |