document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=633208>Question 633208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much gas does it take to mow a whole lawn if it takes 3/4 gallon to mow 6/7 of the whole lawn? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398723 by </B><A HREF=/tutors/aboutme.mpl?userid=GFeliz><B>GFeliz(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=GFeliz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=GFeliz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6/7)/1 = (3/4)/g, where g represents the amount of gas needed\r<BR>\n" );
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document.write( "(6/7)g = (3/4)\r<BR>\n" );
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document.write( "g = (3/4) divided by (6/7)\r<BR>\n" );
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document.write( "g = (3/4) times (7/6)\r<BR>\n" );
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document.write( "g = (7/8) gas is needed </SPAN>\n" );
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