document.write( "Question 633166: solve 2y^2=6y-20 by completing the square \n" ); document.write( "
Algebra.Com's Answer #398699 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "2y^2=6y-20
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document.write( "2y^2-6y = -20
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document.write( "2(y - 3/2)^2 -9/2  = -20 
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document.write( "2(y - 3/2)^2 =  -31/2
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document.write( "  (y-3/2)^2 = -31/4
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document.write( "     y = 3/2 ± isqrt(31)/2
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document.write( "Checking using Quadratic Formula     
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document.write( "2y^2-6y + 20 = 0
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document.write( "\"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "\"y+=+%286+%2B-+sqrt%28+-124+%29%29%2F%284%29+\"
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document.write( "\"y+=+3%2F2+%2B-+i%2Asqrt%28+31%29%2F2\" \n" );
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