document.write( "Question 58273: The length of a rectangle is 12 cm more than its width. A second rectangle is 3cm shorter in width and 5cm longer in length than the first rectangle, and has a perimeter of 68cm. What are the dimensions of this second rectangle.\r
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document.write( "So far, I got first rectangle is L=w+12 and then got confused. I know the second rectangle 2L+2W=68. This question is not from a textbook, but from a worksheet. \n" );
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Algebra.Com's Answer #39869 by faceoff57(108)![]() ![]() You can put this solution on YOUR website! L=w+12 \n" ); document.write( "2L+2w=68 \n" ); document.write( "2(w+17)+2(w-3)=68 \n" ); document.write( "2w+34+2w-6=68 \n" ); document.write( "4w+28=68 \n" ); document.write( "4w=40 \n" ); document.write( "w=10 \n" ); document.write( "THE SECOND RECTANGLE HAS A LENGTH OF 27CM AND A WIDTH OF 7CM. \n" ); document.write( " |