document.write( "Question 633147: 1. perpendicular to and bisecting the line segment whose endpoints are A(-1,6) and B(5,-4). the answer is 3x-5y-1=0. what is the solution of it?
\n" ); document.write( "2. with slope equal to -1 and x-intercept equal to 6. the answer is x+y-6=0. what is the solution?\r
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Algebra.Com's Answer #398687 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( " Line perpendicular to and bisectingthe line segment whose endpoints are A(-1,6) and
\n" ); document.write( "B(5,-4) m = 10/-6 = -5/3 \"m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29\"
\n" ); document.write( "And midpointof the line segment is (2,1) |Midpoint Pt(x,y): ( \"%28x%5B1%5D+%2B+x%5B2%5D%29%2F2\", \"%28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29\")
\n" ); document.write( "New Perpendicular Line:
\n" ); document.write( " m = 3/5 | perpendicular lines have slopes that are the negative reciprocal of one another
\n" ); document.write( " y = mx + b
\n" ); document.write( " y = (3/5)x + b
\n" ); document.write( " 1 = (3/5)2 + b
\n" ); document.write( " -1/5 = b
\n" ); document.write( "y = (3/5)x - 1/5 or 3x-5y -1 = 0\r
\n" ); document.write( "\n" ); document.write( "Line with slope equal to -1 and x-intercept equal to 6
\n" ); document.write( " y = mx + b
\n" ); document.write( " y = -x + b |using ordered pair (6,0) to find b
\n" ); document.write( " 0 = -6 + b
\n" ); document.write( " 6 = b
\n" ); document.write( "y = -x + 6 or x + y-6 = 0 \n" ); document.write( "
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