document.write( "Question 58125: Linear equations using substitution, Thank you !\r
\n" ); document.write( "\n" ); document.write( "x/3+y/5 =1
\n" ); document.write( "x+6y=12\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #39868 by jaya_rohith1@yahoo.com(33)\"\" \"About 
You can put this solution on YOUR website!
x/3+y/5=1 ----- (1)
\n" ); document.write( "x+6y=12 ----- (2)
\n" ); document.write( "(1) implies 5x+3y = 15 ------ (3)
\n" ); document.write( "(3)*2 implies 10x+6y = 30 ----- (4)
\n" ); document.write( "(2) - (4) implies -9x = -18
\n" ); document.write( " x = 2
\n" ); document.write( "substitute x in (2) we get 2+6y=12
\n" ); document.write( " 6y=10
\n" ); document.write( " y=5/3
\n" ); document.write( "
\n" );