document.write( "Question 58125: Linear equations using substitution, Thank you !\r
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document.write( "x/3+y/5 =1
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document.write( "x+6y=12\r
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Algebra.Com's Answer #39868 by jaya_rohith1@yahoo.com(33)![]() ![]() ![]() You can put this solution on YOUR website! x/3+y/5=1 ----- (1) \n" ); document.write( "x+6y=12 ----- (2) \n" ); document.write( "(1) implies 5x+3y = 15 ------ (3) \n" ); document.write( "(3)*2 implies 10x+6y = 30 ----- (4) \n" ); document.write( "(2) - (4) implies -9x = -18 \n" ); document.write( " x = 2 \n" ); document.write( "substitute x in (2) we get 2+6y=12 \n" ); document.write( " 6y=10 \n" ); document.write( " y=5/3 \n" ); document.write( " |