document.write( "Question 632991: A coin collector has 29 dimes and nickels with a total face value of $2.40. (They are actually worth a lot more.) How many of each coin does she have \n" ); document.write( "
Algebra.Com's Answer #398635 by Maths68(1474) You can put this solution on YOUR website! Nickels=x \n" ); document.write( "Dimes=29-x \n" ); document.write( "Total value of all coins= $2.40\r \n" ); document.write( "\n" ); document.write( "(Nickels)(Value of a Nickel)+(Dimes)(Value of a Dime)=Total value of all coins \n" ); document.write( "(x)(0.05)+(29-x)(0.1)=2.40 \n" ); document.write( "0.05x+2.9-0.1x=2.40 \n" ); document.write( "0.05x-0.1x=2.40-2.9 \n" ); document.write( "-0.05x=-0.5 \n" ); document.write( "-0.05x/-0.05=-0.5/-0.05 \n" ); document.write( "x=10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Nickels=x=10 \n" ); document.write( "Dimes=29-x=29-10=19\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "===== \n" ); document.write( "10*0.05+19*0.1=2.4 \n" ); document.write( "0.5+1.9=2.4 \n" ); document.write( "2.4=2.4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |