document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=633034>Question 633034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An airplane leaves los angeles for Denver at a speed of 450 mph.Thirty min later,a plane going from Denver yo los Angeles leaves Denver,which is 850 miles from los Angeles,at a speed of 520 mph.When they meet, how far are they from Denver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398624 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> After 30 minutes the first plane has traveled 225 miles from Los Angeles so there are 850-225=625 miles left to Denver. Let t be the time in hours before the 2 planes meet. The first plane will travel 450*t miles. The second plane will travel 520*t miles. The sum of the 2 distances must be 625 miles so.  450*t+520*t=625.   970*t=625.  t=625/970.   t=0.644 hours.   The distance from Denver is 520*0.644=334.88 miles. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );