document.write( "Question 633016: complete the ordered pair for the equation3x+4y=12 (0, ),( ,0),(-4, ) \n" ); document.write( "

Algebra.Com's Answer #398600 by Maths68(1474) $\"\"$ $\"About$

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3x+4y=12
\n" ); document.write( "(0, )
\n" ); document.write( "3(0)+4y=12
\n" ); document.write( "4y=12
\n" ); document.write( "y=12/4
\n" ); document.write( "y=3
\n" ); document.write( "(0,3)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "( ,0)
\n" ); document.write( "3x+4y=12
\n" ); document.write( "3x+4(0)=12
\n" ); document.write( "3x=12
\n" ); document.write( "x=12/3
\n" ); document.write( "x=4
\n" ); document.write( "(4,0)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(-4, )
\n" ); document.write( "3(-4)+4y=12
\n" ); document.write( "-12+4y=12
\n" ); document.write( "4y=12+12
\n" ); document.write( "4y=24
\n" ); document.write( "y=24/4
\n" ); document.write( "y=6
\n" ); document.write( "(-4,6)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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