document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57537>Question 57537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4y^5+12y^4-40y^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39859 by </B><A HREF=/tutors/aboutme.mpl?userid=BGluvsmath><B>BGluvsmath(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BGluvsmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4y^5+12y^4-40y^3<BR>\n" );
document.write( "To simplify, you can factor out 4y^3 from each term, which leaves y^2+3y-10, so the final answer is 4y^3(y^2+3y-10). </SPAN>\n" );
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