document.write( "Question 632899: help! Help!
\n" ); document.write( "problem 24. using perimeter formula find the perimeter of the rectangle in terms
\n" ); document.write( "of x. one side is x the other is 3x-8
\n" ); document.write( "problem 25. There is an equilateral triangle. use formula to find its perimeter in terms of x. there is a2x on one side
\n" ); document.write( "problem 26. a. persume the perimeters of rectangle in problem 24 and the triangle in problrm 25 are equal,use your answer to 24. and 25 ,find x.
\n" ); document.write( "26. B. use answers 24,25,26a calcuate the perimeters of both the rectangle in 24 and the triangle in 25(if calcuations are correct perimeters should be equal)
\n" ); document.write( "everything I did is all messed up I am lost,please help me, please
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Algebra.Com's Answer #398546 by KMST(5328)\"\" \"About 
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The perimeter of any polygon is calculated by adding the lengths of all the sides.
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\n" ); document.write( "24. Since a rectangle has two pairs of congruent sides, two sides will have a length L, and the other two sides will have a length W, for a perimeter
\n" ); document.write( "\"P=2L%2B2W\" or \"highlight%28P=2%28L%2BW%29%29\"
\n" ); document.write( "In this case \"L%2BW=x%2B3x-8=4x-8\" and \"P=2%284x-8%29\" --> \"highlight%28P=8x-16%29\"
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\n" ); document.write( "25. An equilateral triangle has three congruent sides, so if the length of each side is S, the perimeter, P, is
\n" ); document.write( "\"P=3S\"
\n" ); document.write( "If the length of each side is \"S=2x\", the perimeter is
\n" ); document.write( "\"P=3%282x%29\" --> \"P=3%2A2%2Ax\" --> \"highlight%28P=6x%29\"
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\n" ); document.write( "26.
\n" ); document.write( "a. If we presume that the perimeters of the rectangle in problem 24 and the triangle in problem 25 are equal,
\n" ); document.write( "\"8x-16=6x\" --> \"8x-6x-16=6x-6x\" --> \"2x-16=0\" --> \"2x-16%2B16=0%2B16\" --> \"2x=16\" --> \"2x%2F2=16%2F2\" --> \"highlight%28x=8%29\"
\n" ); document.write( "b.Substituting \"x=8\", the perimeter for the rectangle is
\n" ); document.write( "\"P=8x-16\" --> \"P=8%2A8-16\" --> \"P=64-16\" --> \"highlight%28P=48%29\"
\n" ); document.write( "Substituting \"x=8\", the perimeter for the triangle is
\n" ); document.write( "\"P=6x\" --> \"P=6%2A8\" --> \"highlight%28P=48%29\"
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