document.write( "Question 58230: A spider has 8 legs and no wings. A dragonfly has 6 legs and 2 pairs of wings. A cicada has 6 legs and one pair of wings. We have all 3 kinds and a total of 18 insects in a cage. This gives us a total of 118 legs and 20 pairs of wings. How many insects do we have of each kind? \n" ); document.write( "
Algebra.Com's Answer #39851 by checkley71(8403)\"\" \"About 
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8L=S
\n" ); document.write( "6L+2W=D
\n" ); document.write( "6L+1W=C\r
\n" ); document.write( "\n" ); document.write( "S+D+C=18
\n" ); document.write( "TO GET 118 LEGS & 20 PAIR OF WINGS WE NEED\r
\n" ); document.write( "\n" ); document.write( "5 SPIDERS+7 DRAGON FLIES+6 CICADA\r
\n" ); document.write( "\n" ); document.write( "5 SPIDERS HAVE 40 LEGS
\n" ); document.write( "7 DRAGONS HAVE 42 LEGS & 14 SETS OF WINGS
\n" ); document.write( "6 CICADA HAVE 36 LEGA & 6 SETS OF WINGS
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\n" ); document.write( "18 INSECTS HAVE 118 LEGS & 20 SETS OF WINGS (MAKE UP A TABLE WITH ALL THE DATA AND START FILLING IN THE BOXES)
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