document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58235>Question 58235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Equations expressed it in standard form.  Please help me with the steps, I need some understanding in how it is done.  Thanks, and thanks for this website.\r<BR>\n" );
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document.write( "Through (8,3) and (-4,3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39845 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST FIND THE SLOPE (Y2-Y1)/(X2-X1)<BR>\n" );
document.write( "(3-3)/(-4-8)<BR>\n" );
document.write( "0/-12=0 THUS THE SLOPE=0 AND THE LINE IS A HORIZONTAL LINE THROUGH THE POINT Y=3<BR>\n" );
document.write( "THUS THE EQUATION IS<BR>\n" );
document.write( "Y=0*X+3 OR<BR>\n" );
document.write( "Y=3 </SPAN>\n" );
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