document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58226>Question 58226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to write an equation of the line and express it in standard form. Can someone please show me how?  Thanks!\r<BR>\n" );
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document.write( "Through (-3,5) and (5,3)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39839 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST WE FIND THE SLOPE (Y2-Y1)/(X2-X1)<BR>\n" );
document.write( "(3-5)/(5+3)<BR>\n" );
document.write( "-2/8<BR>\n" );
document.write( "-1/4 OR -.25 NOW WE USE THIS AS THE m VALUE IN THE STANDARD LINE FORMULAR<BR>\n" );
document.write( "Y=mX+b<BR>\n" );
document.write( "Y=-.25X+b NOW WE SUBSTITE EITH SET OF POINTS FOR X & Y<BR>\n" );
document.write( "5=-.25*-3+b & SOLVE FOR b<BR>\n" );
document.write( "5=.75+b<BR>\n" );
document.write( "5-.75=b<BR>\n" );
document.write( "b=4.25<BR>\n" );
document.write( "THUS WE HAVE<BR>\n" );
document.write( "Y=-.25X+4.25<BR>\n" );
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