document.write( "Question 632433: find an irratational number between .757575... and .767676... \n" ); document.write( "
Algebra.Com's Answer #398388 by KMST(5397)\"\" \"About 
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The number 0.757575... is \"75%2F99\" and 0.767676... is \"76%2F99\".
\n" ); document.write( "You can figure out 0.757575... as a fraction because
\n" ); document.write( "if n=0.757575... , then 100n=75.757575... and subtracting one equation from the other, you get
\n" ); document.write( "100n-n=75 --> (100-1)n=75 --> 99n=75 --> \"n=75%2F99\"
\n" ); document.write( "You can figure out that 0.767676... = \"76%2F99\" similarly.
\n" ); document.write( "You can choose an integer m between \"75%5E2=5625\" and \"76%5E2=5776\"
\n" ); document.write( "(\"2625%3Cm%3C5776\"),
\n" ); document.write( "and then \"sqrt%28m%29%2F99\" will be an irrational number between 0.757575... and 0.767676... because\r
\n" ); document.write( "\n" ); document.write( "0.757575... = \"75%2F99=sqrt%285625%29%2F99%3Csqrt%28m%29%2F99%3Csqrt%285776%29%2F99=76%2F99\" = 0.767676...\r
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