document.write( "Question 632433: find an irratational number between .757575... and .767676... \n" ); document.write( "
Algebra.Com's Answer #398388 by KMST(5397) You can put this solution on YOUR website! The number 0.757575... is \n" ); document.write( "You can figure out 0.757575... as a fraction because \n" ); document.write( "if n=0.757575... , then 100n=75.757575... and subtracting one equation from the other, you get \n" ); document.write( "100n-n=75 --> (100-1)n=75 --> 99n=75 --> \n" ); document.write( "You can figure out that 0.767676... = \n" ); document.write( "You can choose an integer m between \n" ); document.write( "( \n" ); document.write( "and then \n" ); document.write( "\n" ); document.write( "0.757575... = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |