document.write( "Question 58223: sinx sinx\r\n" );
document.write( "------------ + ------------\r\n" );
document.write( " (1 + cosx) (1 - cosx)
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document.write( "
Algebra.Com's Answer #39838 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " sinx sinx\r\n" ); document.write( "------------ + ------------\r\n" ); document.write( " (1 + cosx) (1 - cosx)\r\n" ); document.write( "\r\n" ); document.write( "The LCD is (1 + cosx)(1 - cosx)\r\n" ); document.write( "\r\n" ); document.write( "Multiply the first fraction by \r\n" ); document.write( "\r\n" ); document.write( "(1 - cosx) \r\n" ); document.write( "---------- \r\n" ); document.write( "(1 - cosx)\r\n" ); document.write( "\r\n" ); document.write( "which is OK to do since it equals 1:\r\n" ); document.write( "\r\n" ); document.write( " sinx(1 - cosx) sinx\r\n" ); document.write( "---------------------- + ------------\r\n" ); document.write( " (1 + cosx)(1 - cosx) (1 - cosx)\r\n" ); document.write( "\r\n" ); document.write( "Now multiply the second fraction by \r\n" ); document.write( "\r\n" ); document.write( "(1 + cosx) \r\n" ); document.write( "---------- \r\n" ); document.write( "(1 + cosx)\r\n" ); document.write( "\r\n" ); document.write( "which is also OK to do since it equals 1:\r\n" ); document.write( "\r\n" ); document.write( " sinx(1 - cosx) sinx(1 + cosx)\r\n" ); document.write( "---------------------- + ----------------------\r\n" ); document.write( " (1 + cosx)(1 - cosx) (1 - cosx)(1 + cosx)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Multiply everything out\r\n" ); document.write( "\r\n" ); document.write( " sinx - sinx·cosx sinx + sinx·cosx\r\n" ); document.write( "---------------------- + ----------------------\r\n" ); document.write( " 1 - cos²x 1 - cos²x\r\n" ); document.write( "\r\n" ); document.write( "Combine the numerators over the LCD:\r\n" ); document.write( "\r\n" ); document.write( " sinx - sinx·cosx + sinx + sinx·cosx\r\n" ); document.write( "-------------------------------------\r\n" ); document.write( " 1 - cos²x\r\n" ); document.write( "\r\n" ); document.write( "the 2nd and 4th terms on top cancel out.\r\n" ); document.write( "The 1st and 3rd terms on top combine to give 2sinx \r\n" ); document.write( "\r\n" ); document.write( " 2sinx \r\n" ); document.write( "-------------\r\n" ); document.write( " 1 - cos²x\r\n" ); document.write( "\r\n" ); document.write( "Use the identity sin²x + cos²x = 1, which\r\n" ); document.write( "can be written sin²x = 1 - cos²x to replace\r\n" ); document.write( "the bottom by sin²x\r\n" ); document.write( "\r\n" ); document.write( " 2sinx \r\n" ); document.write( "---------\r\n" ); document.write( " sin²x\r\n" ); document.write( "\r\n" ); document.write( "Divide top and bottom by sinx, and get\r\n" ); document.write( "\r\n" ); document.write( " 2 \r\n" ); document.write( "------\r\n" ); document.write( " sinx \r\n" ); document.write( "\r\n" ); document.write( "which can be written\r\n" ); document.write( "\r\n" ); document.write( " 2cscx\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |