document.write( "Question 58223:
    sinx           sinx\r\n" );
document.write( "------------ + ------------\r\n" );
document.write( " (1 + cosx)     (1 - cosx)
\n" ); document.write( "

Algebra.Com's Answer #39838 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
 \r\n" );
document.write( "    sinx           sinx\r\n" );
document.write( "------------ + ------------\r\n" );
document.write( " (1 + cosx)     (1 - cosx)\r\n" );
document.write( "\r\n" );
document.write( "The LCD is (1 + cosx)(1 - cosx)\r\n" );
document.write( "\r\n" );
document.write( "Multiply the first fraction by \r\n" );
document.write( "\r\n" );
document.write( "(1 - cosx)         \r\n" );
document.write( "---------- \r\n" );
document.write( "(1 - cosx)\r\n" );
document.write( "\r\n" );
document.write( "which is OK to do since it equals 1:\r\n" );
document.write( "\r\n" );
document.write( "    sinx(1 - cosx)           sinx\r\n" );
document.write( "---------------------- + ------------\r\n" );
document.write( " (1 + cosx)(1 - cosx)     (1 - cosx)\r\n" );
document.write( "\r\n" );
document.write( "Now multiply the second fraction by \r\n" );
document.write( "\r\n" );
document.write( "(1 + cosx)         \r\n" );
document.write( "---------- \r\n" );
document.write( "(1 + cosx)\r\n" );
document.write( "\r\n" );
document.write( "which is also OK to do since it equals 1:\r\n" );
document.write( "\r\n" );
document.write( "    sinx(1 - cosx)           sinx(1 + cosx)\r\n" );
document.write( "---------------------- + ----------------------\r\n" );
document.write( " (1 + cosx)(1 - cosx)     (1 - cosx)(1 + cosx)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Multiply everything out\r\n" );
document.write( "\r\n" );
document.write( "    sinx - sinx·cosx        sinx + sinx·cosx\r\n" );
document.write( "---------------------- + ----------------------\r\n" );
document.write( "      1 - cos²x               1 - cos²x\r\n" );
document.write( "\r\n" );
document.write( "Combine the numerators over the LCD:\r\n" );
document.write( "\r\n" );
document.write( " sinx - sinx·cosx + sinx + sinx·cosx\r\n" );
document.write( "-------------------------------------\r\n" );
document.write( "            1 - cos²x\r\n" );
document.write( "\r\n" );
document.write( "the 2nd and 4th terms on top cancel out.\r\n" );
document.write( "The 1st and 3rd terms on top combine to give 2sinx \r\n" );
document.write( "\r\n" );
document.write( "    2sinx \r\n" );
document.write( "-------------\r\n" );
document.write( "  1 - cos²x\r\n" );
document.write( "\r\n" );
document.write( "Use the identity sin²x + cos²x = 1, which\r\n" );
document.write( "can be written sin²x = 1 - cos²x to replace\r\n" );
document.write( "the bottom by sin²x\r\n" );
document.write( "\r\n" );
document.write( "  2sinx \r\n" );
document.write( "---------\r\n" );
document.write( "  sin²x\r\n" );
document.write( "\r\n" );
document.write( "Divide top and bottom by sinx, and get\r\n" );
document.write( "\r\n" );
document.write( "  2 \r\n" );
document.write( "------\r\n" );
document.write( " sinx     \r\n" );
document.write( "\r\n" );
document.write( "which can be written\r\n" );
document.write( "\r\n" );
document.write( " 2cscx\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );