document.write( "Question 632564: Speed of sound through water caries by temperature
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document.write( "s=-0.0276t^2 + 9.1558t + 4354.7 (between freezing and boiling)
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document.write( "s= speed in feet/second, t= temperature Fahrenheit\r
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document.write( "I dropped a loud waterproof buzzer in the ocean. My friend who was 4700 feet away heard it 1 second later. What is the temperature of the water? (nearest degree fahrenheit) \n" );
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Algebra.Com's Answer #398367 by nerdybill(7384) You can put this solution on YOUR website! Speed of sound through water caries by temperature \n" ); document.write( "s=-0.0276t^2 + 9.1558t + 4354.7 (between freezing and boiling) \n" ); document.write( "s= speed in feet/second, t= temperature Fahrenheit \n" ); document.write( "I dropped a loud waterproof buzzer in the ocean. My friend who was 4700 feet away heard it 1 second later. What is the temperature of the water? (nearest degree fahrenheit) \n" ); document.write( ". \n" ); document.write( "Set s to 4700/1 and solve for t: \n" ); document.write( "4700 = -0.0276t^2 + 9.1558t + 4354.7 \n" ); document.write( "0 = -0.0276t^2 + 9.1558t - 345.3 \n" ); document.write( "Using the \"quadratic equation\" we get: \n" ); document.write( "x = {43.4, 288.3} \n" ); document.write( "Throw out the 288 because it is outside the boiling point leaving: \n" ); document.write( "x = 43 degrees \n" ); document.write( ". \n" ); document.write( "Details of quadratic formula: \n" ); document.write( "
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