document.write( "Question 632564: Speed of sound through water caries by temperature
\n" ); document.write( "s=-0.0276t^2 + 9.1558t + 4354.7 (between freezing and boiling)
\n" ); document.write( "s= speed in feet/second, t= temperature Fahrenheit\r
\n" ); document.write( "\n" ); document.write( "I dropped a loud waterproof buzzer in the ocean. My friend who was 4700 feet away heard it 1 second later. What is the temperature of the water? (nearest degree fahrenheit)
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Algebra.Com's Answer #398367 by nerdybill(7384)\"\" \"About 
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Speed of sound through water caries by temperature
\n" ); document.write( "s=-0.0276t^2 + 9.1558t + 4354.7 (between freezing and boiling)
\n" ); document.write( "s= speed in feet/second, t= temperature Fahrenheit
\n" ); document.write( "I dropped a loud waterproof buzzer in the ocean. My friend who was 4700 feet away heard it 1 second later. What is the temperature of the water? (nearest degree fahrenheit)
\n" ); document.write( ".
\n" ); document.write( "Set s to 4700/1 and solve for t:
\n" ); document.write( "4700 = -0.0276t^2 + 9.1558t + 4354.7
\n" ); document.write( "0 = -0.0276t^2 + 9.1558t - 345.3
\n" ); document.write( "Using the \"quadratic equation\" we get:
\n" ); document.write( "x = {43.4, 288.3}
\n" ); document.write( "Throw out the 288 because it is outside the boiling point leaving:
\n" ); document.write( "x = 43 degrees
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\n" ); document.write( "Details of quadratic formula:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-0.0276x%5E2%2B9.1558x%2B-345.3+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%289.1558%29%5E2-4%2A-0.0276%2A-345.3=45.70755364\".
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\n" ); document.write( " Discriminant d=45.70755364 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-9.1558%2B-sqrt%28+45.70755364+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%289.1558%29%2Bsqrt%28+45.70755364+%29%29%2F2%5C-0.0276+=+43.3888373932807\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%289.1558%29-sqrt%28+45.70755364+%29%29%2F2%5C-0.0276+=+288.34304666469\"
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\n" ); document.write( " Quadratic expression \"-0.0276x%5E2%2B9.1558x%2B-345.3\" can be factored:
\n" ); document.write( " \"-0.0276x%5E2%2B9.1558x%2B-345.3+=+-0.0276%28x-43.3888373932807%29%2A%28x-288.34304666469%29\"
\n" ); document.write( " Again, the answer is: 43.3888373932807, 288.34304666469.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-0.0276%2Ax%5E2%2B9.1558%2Ax%2B-345.3+%29\"
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