document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=632612>Question 632612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3cm more than the width. The area is 70cm^2. Find the dimensions of the rectangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398364 by </B><A HREF=/tutors/aboutme.mpl?userid=art123><B>art123(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=art123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width=x<BR>\n" );
document.write( "then length=3+x<BR>\n" );
document.write( "area=length*width<BR>\n" );
document.write( "therefore area=x*(x+3)<BR>\n" );
document.write( "given area=70cm^2<BR>\n" );
document.write( "70=x^2+3x<BR>\n" );
document.write( "x^2+3x-70=0<BR>\n" );
document.write( "x^2+10x-7x-70=0<BR>\n" );
document.write( "x(x+10)-7(x+10)=0<BR>\n" );
document.write( "(x+10)(x-7)=0<BR>\n" );
document.write( "(x-7)=0<BR>\n" );
document.write( "therefore x=7<BR>\n" );
document.write( "ignore x=-10 as it is negative value<BR>\n" );
document.write( "therefore width=7cm<BR>\n" );
document.write( "          length=7+3=10cm </SPAN>\n" );
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