document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58161>Question 58161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If twice the square of a positive number is added to the product of -1 and the number,the result is 45.Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39836 by </B><A HREF=/tutors/aboutme.mpl?userid=faceoff57><B>faceoff57(108)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=faceoff57><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=faceoff57><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2+-1x=45<BR>\n" );
document.write( "2x^2-x-45=0<BR>\n" );
document.write( "(2x+9)(x-5)=0<BR>\n" );
document.write( "2x+9=0            <BR>\n" );
document.write( "2x=-9             <BR>\n" );
document.write( "x=-9/2<BR>\n" );
document.write( "OR x-5=0  x=5<BR>\n" );
document.write( "THE NUMBER IS 5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );