document.write( "Question 632554: There is a solution whixh contains 40% alcohol and 60%water.
\n" ); document.write( "how much percentage of water we need to add to make alcohol 1%...??? \n" ); document.write( "

Algebra.Com's Answer #398348 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The original solution is $\"+.4%2F1=+.4+\"$ ( in some units, gallons, etc )
\n" ); document.write( "Let $\"+x+\"$ = the amount of water to be added in same units
\n" ); document.write( "You're looking for $\"+.4+%2F+%28+1+%2B+x+%29+=+.01+\"$
\n" ); document.write( " $\"+.4+=+.01%2A%28+1+%2B+x+%29+\"$
\n" ); document.write( " $\"+.4+=+.01+%2B+.01x+\"$
\n" ); document.write( " $\"+.01x+=+.4+-+.01+\"$
\n" ); document.write( " $\"+.01x+=+.39+\"$
\n" ); document.write( " $\"+x+=+39+\"$
\n" ); document.write( "You had 60% water to begin with
\n" ); document.write( "Now you have $\"+%28+.6+%2B+x+%29+%2F+%28+1+%2B+x+%29+=+39.6+%2F+40+\"$
\n" ); document.write( " $\"+%28+39.6%2F40%29%2A100+=+99+\"$ percent water
\n" ); document.write( "( that figures since 1 - .01 = 99 )
\n" ); document.write( " $\"+99+-+60+=+39+\"$
\n" ); document.write( "So you increase the percentage of water by 39% \n" ); document.write( "

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