document.write( "Question 632437: Find the surface area of a cylinder with a base area of 49 π in2 and a height that is twice the radius of its base. \n" ); document.write( "
Algebra.Com's Answer #398313 by lwsshak3(11628)\"\" \"About 
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Find the surface area of a cylinder with a base area of 49 π in2 and a height that is twice the radius of its base.
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\n" ); document.write( "formula for surface area of a cylinder=πr√(r^2+h^2), r-radius of circular base, h=height
\n" ); document.write( "given area of circular base=49π in^2=πr^2
\n" ); document.write( "49π in^2=πr^2
\n" ); document.write( "r^2=49
\n" ); document.write( "r=√49=7
\n" ); document.write( "h=2r=14
\n" ); document.write( "..
\n" ); document.write( "πr√(r^2+h^2)=π*7√(7^2+14^2)=21.99√(49+196)=21.99√245=344.20
\n" ); document.write( "surface area of a cylinder=344.20 in^3 \n" ); document.write( "
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