document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58172>Question 58172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 centimeters less than three times its width.If the area is 40 square centimeters,find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39826 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W-2<BR>\n" );
document.write( "L*W=40<BR>\n" );
document.write( "(3W-2)W=40<BR>\n" );
document.write( "3W^2-2W-40=0<BR>\n" );
document.write( "(3W+10)(W-4)=0<BR>\n" );
document.write( "3W+10=0<BR>\n" );
document.write( "3W=10<BR>\n" );
document.write( "W=-10/3 NOT A SOLUTION<BR>\n" );
document.write( "W-4=0<BR>\n" );
document.write( "W=4<BR>\n" );
document.write( "L=3*4-2<BR>\n" );
document.write( "L=12-2<BR>\n" );
document.write( "L=10<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "10*4=40<BR>\n" );
document.write( "40=40 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );