document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=632353>Question 632353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you wrap a piece of wire 8 times around a pipe and the length of the pipe is 20cm and the circumference is 6cm, what is the length of the wire? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398252 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you wrap a piece of wire 8 times around a pipe and the length of the pipe is 20cm and the circumference is 6cm, what is the length of the wire?<BR>\n" );
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document.write( "If you mean the wire is wrapped in a helical manner along the length of the pipe, then:<BR>\n" );
document.write( "If you unwrap it on a flat surface, you get a right triangle.  The base is 8 turns of the pipe = 8*6 = 48 cm<BR>\n" );
document.write( "The other leg is the length of the pipe = 20 cm<BR>\n" );
document.write( "The length of the wire is the hypotenuse<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w+=+sqrt%2848%5E2+%2B+20%5E2%29 ALIGN=MIDDLE  ALT=\"w+=+sqrt%2848%5E2+%2B+20%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "w = 52 cm<BR>\n" );
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