document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=632364>Question 632364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sandy and Kelvin live 385 miles apart. They each leave home at 3:00 P.M. Sandy drives 60 mph, and Kelvin drives 50 mph. At what time will they meet?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398236 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = number of hours driving until they meet.<BR>\n" );
document.write( "Distance of Sandy = R*T = 60x<BR>\n" );
document.write( "Distance of Kelvin = R*T= 50x\r<BR>\n" );
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document.write( "Total Distance = 385 miles<BR>\n" );
document.write( "60x + 50x = 385<BR>\n" );
document.write( "110x = 385<BR>\n" );
document.write( "x=385/110=3 55/110<BR>\n" );
document.write( "x=3.5 hours\r<BR>\n" );
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document.write( "Since they left at 3:00 pm, add 3.5 hours, and they will meet at 6:30 pm.\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole State College of Florida </SPAN>\n" );
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