document.write( "Question 632364: Sandy and Kelvin live 385 miles apart. They each leave home at 3:00 P.M. Sandy drives 60 mph, and Kelvin drives 50 mph. At what time will they meet?\r
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Algebra.Com's Answer #398235 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Question states*** They each drive the same amount of time:  t = D/r
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document.write( "Let x represent the amount of distance driven by Kelvin
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document.write( "       | Cross Multiplying to solve
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document.write( "       60x = 50(385-x)
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document.write( "      110x = 19250
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document.write( "         x = 175, distance driven by Kelvin.  t = 175/50 =3.5 hrs 
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document.write( "left home at 3:00 P.M. met at 6:30 P.M.\r
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document.write( "and(just checking...) Sandy's time = 210/60 = 3.5 hrs  \n" );
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