document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=632296>Question 632296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My problem is to do with the hypotenuse of a certain trig problem. The adjacent is 8.25, the opposite unknown and we have to find W, the hypotenuse. The triangle is right-angled, and the given theta is 63 degrees, 32 minutes. I have worked out cos-theta = A/H, and then cos63 32'= 8.25/W. However, when I attempt to work out this problem, the answers for the problem, a hypotenuse,always comes up smaller than the other sides (O and A). Am I doing something wrong when H = 3.68 cm and the O = 8.25 cm?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398203 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> My problem is to do with the hypotenuse of a certain trig problem. The adjacent is 8.25, the opposite unknown and we have to find W, the hypotenuse. The triangle is right-angled, and the given theta is 63 degrees, 32 minutes. I have worked out cos-theta = A/H, and then cos63 32'= 8.25/W. However, when I attempt to work out this problem, the answers for the problem, a hypotenuse,always comes up smaller than the other sides (O and A). Am I doing something wrong when H = 3.68 cm and the O = 8.25 cm? <BR>\n" );
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document.write( "x=63º32'&#8776;63.53º<BR>\n" );
document.write( "A=adjacent side=8.25<BR>\n" );
document.write( "O=opposite side<BR>\n" );
document.write( "H=hypotenuse<BR>\n" );
document.write( "..<BR>\n" );
document.write( "cosx=A/H=8.25/H<BR>\n" );
document.write( "H=8.25/cosx=8.25/cos 63.53&#8776;18.51<BR>\n" );
document.write( "sinx=O/H<BR>\n" );
document.write( "O=H*sinx=18.51*sin63.53&#8776;16.57<BR>\n" );
document.write( "..<BR>\n" );
document.write( "opposite side&#8776;16.57 cm<BR>\n" );
document.write( "hypotenuse&#8776;18.5 cm<BR>\n" );
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