document.write( "Question 632322: The side of a square has length s . The length of a rectangle is 4 m more than the side of the square and the width of the rectangle is 2 m less than the side of the square. The perimeter of the rectangle is 24 m less than twice the perimeter of the square. Find the dimensions of each figure. \n" ); document.write( "
Algebra.Com's Answer #398196 by mananth(16946)\"\" \"About 
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Perimeter of square = 4s\r
\n" ); document.write( "\n" ); document.write( "twice perimeter of square = 4s*2 = 8s\r
\n" ); document.write( "\n" ); document.write( "Length of rectangle = s+4\r
\n" ); document.write( "\n" ); document.write( "Width of rectangle = s-2\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2(l+w)\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2(s+4+s-2)
\n" ); document.write( "=2(2s+2)
\n" ); document.write( "=4s+4
\n" ); document.write( "8s-(4s+4) =24\r
\n" ); document.write( "\n" ); document.write( "8s-4s-4=24
\n" ); document.write( "4s-4=24
\n" ); document.write( "4s=28
\n" ); document.write( "s=7 \r
\n" ); document.write( "\n" ); document.write( "side of square = 7m\r
\n" ); document.write( "\n" ); document.write( "Length of lectangle = 7+4=11m
\n" ); document.write( "width of rectangle = 7-2=5m\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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