document.write( "Question 632316: find the equation of the line passing (0,1) parallel to the line 2x-3y=6 \n" ); document.write( "
Algebra.Com's Answer #398194 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Equation of the line slope-intercept form \n" ); document.write( "y=mx+b \n" ); document.write( "Given \n" ); document.write( "Equation of the Given line \n" ); document.write( "2x-3y=6 \n" ); document.write( "-3y=-2x+6 \n" ); document.write( "-3y/-3=(-2x+6)/-3 \n" ); document.write( "y=2x/3-2 \n" ); document.write( "y=(2/3)x-2 \n" ); document.write( "Compare with the equation of line slope-intercept form \n" ); document.write( "Slope of the given = m = 2/3 \n" ); document.write( "Since lines are parallel their slope will be same \n" ); document.write( "Slope of the required line = m = 2/3 \n" ); document.write( "Point (0, 1) \n" ); document.write( "We have a point and slope we can get easily the require line equation. \n" ); document.write( "Use Equation of the line point-slope form \n" ); document.write( "m = y2-y1/x2-x1 \n" ); document.write( "Put the values in above equation, we have \n" ); document.write( "2/3=(y-1)/(x-0) \n" ); document.write( "2/3=(y-1)/x \n" ); document.write( "2x=3(y-1) \n" ); document.write( "2x=3y-3 \n" ); document.write( "-3y=-2x-3 \n" ); document.write( "-3y/-3=-(2x+3)/-3 \n" ); document.write( "y=2x/3+3/3 \n" ); document.write( "y=(2/3)x+1 \n" ); document.write( "Above equation is the equation of the required line\r \n" ); document.write( "\n" ); document.write( "Graph \n" ); document.write( "===== \n" ); document.write( "y=(2/3)x-2 (Given line in green) \n" ); document.write( "y=(2/3)x+1 (Required line in Red) \n" ); document.write( " |