document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=632314>Question 632314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of 60% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 50% antifreeze? Use the six-step method. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398190 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -------------- 	percent	----------------	Amount										<BR>\n" );
document.write( "Antifreeze I	20	----------------			100	gal							<BR>\n" );
document.write( "Antifreeze II	60	----------------			x	gal							<BR>\n" );
document.write( "Mixture	50	----------------	100	+	x	gal							<BR>\n" );
document.write( "													<BR>\n" );
document.write( "20	*	100	+	60	x	=	50	(	100	+	x	)	<BR>\n" );
document.write( "2000	+	60	x	=	5000	+	50	x					<BR>\n" );
document.write( "60	x		-50	x	=	-2000	+	5000					<BR>\n" );
document.write( "10	x	=	3000										<BR>\n" );
document.write( "/	10												<BR>\n" );
document.write( "x	=	300		gal	Antifreeze II								<BR>\n" );
document.write( "													<BR>\n" );
document.write( "m.ananth@hotmail.ca													<BR>\n" );
document.write( "													<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );