document.write( "Question 632305: the points A(1,5),B(4,-1),C(-2,-4) forms a triangle ABC.Prove that the triangle is right angled and find the area.....plezz help me..........\r
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Algebra.Com's Answer #398182 by reviewermath(1029)\"\" \"About 
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a = distance between B and C = \"sqrt%28%28-4-%28-1%29%29%5E2+%2B+%28-2-4%29%5E2%29+=+sqrt%2845%29+\"
\n" ); document.write( "b = distance between A and C = \"sqrt%28%28-4-5%29%5E2+%2B+%28-2-1%29%5E2%29+=+sqrt%2890%29\"
\n" ); document.write( "c = distance between A and B = \"sqrt%28%28-1-5%29%5E2+%2B+%284-1%29%5E2%29+=+sqrt%2845%29\"\r
\n" ); document.write( "\n" ); document.write( "Therefore \"a%5E2+%2B+c%5E2+=+b%5E2\" because \"%28sqrt%2845%29%29%5E2+%2B+%28sqrt%2845%29%29%5E2+=+%28sqrt%2890%29%29%5E2\".\r
\n" ); document.write( "\n" ); document.write( "The sides satisfy the Pythagorean Theorem, therefore triangle ABC is a right triangle with angle B as a right angle.\r
\n" ); document.write( "\n" ); document.write( "the area is equal to
\n" ); document.write( "\"A+=+%28base%29%28height%29%2F2\"
\n" ); document.write( "\"A+=+%28sqrt%2845%29%29%28sqrt%2845%29%29%2F2\"
\n" ); document.write( "\"highlight%28A+=+22.5%29\" square units
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