document.write( "Question 632223: I'm supposed to find the solutions of x for the equation:\r
\n" ); document.write( "\n" ); document.write( "27x^3=(x+5)^3\r
\n" ); document.write( "\n" ); document.write( "I tried using the difference of cubes where a=(x+5)^3 and b=27x^3 but running through it gave a polynomial to the 6th power, which doesn't do me much good. Please help. \n" ); document.write( "

Algebra.Com's Answer #398171 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Try a simpler approach:
\n" ); document.write( " $\"27x%5E3+=+%28x%2B5%29%5E3\"$ Rewrite as:
\n" ); document.write( " $\"%283x%29%5E3+=+%28x%2B5%29%5E3\"$ Take the cube root of both sides.
\n" ); document.write( " $\"3x+=+x%2B5\"$ Subtract x from both sides.
\n" ); document.write( " $\"2x+=+5\"$ Finally, divide both sides by 2.
\n" ); document.write( " $\"x+=+2.5\"$ \n" ); document.write( "

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