document.write( "Question 632223: I'm supposed to find the solutions of x for the equation:\r
\n" ); document.write( "\n" ); document.write( "27x^3=(x+5)^3\r
\n" ); document.write( "\n" ); document.write( "I tried using the difference of cubes where a=(x+5)^3 and b=27x^3 but running through it gave a polynomial to the 6th power, which doesn't do me much good. Please help.
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Algebra.Com's Answer #398140 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Your error, I think, was stating that and when in fact you should have started with and , which would lead you to and \r
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\n" ); document.write( "\n" ); document.write( "Then using the pattern to write:\r
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\n" ); document.write( "\n" ); document.write( "You can take it from here. You should get a linear binomial factor and a quadratic trinomial on which you will need to use the quadratic formula. The net result will be one real root and a pair of complex conjugates.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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