document.write( "Question 632223: I'm supposed to find the solutions of x for the equation:\r
\n" ); document.write( "\n" ); document.write( "27x^3=(x+5)^3\r
\n" ); document.write( "\n" ); document.write( "I tried using the difference of cubes where a=(x+5)^3 and b=27x^3 but running through it gave a polynomial to the 6th power, which doesn't do me much good. Please help.
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Algebra.Com's Answer #398138 by reviewermath(1029)\"\" \"About 
You can put this solution on YOUR website!
Using the difference of two cubes where \"a%5E3+=+%28x%2B5%29%5E3\" and \"b%5E3=27x%5E3\".
\n" ); document.write( "\"a%5E3-b%5E3+=+0+\"
\n" ); document.write( "\"%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29+=+0\"
\n" ); document.write( "\"%28%28x%2B5%29+-+3x%29%2A%28%28x%2B5%29%5E2+%2B+3x%28x%2B5%29+%2B+%283x%29%5E2%29+=+0\"
\n" ); document.write( "\"%28-2x+%2B+5%29%2A%28x%5E2+%2B+10x+%2B+25+%2B+3x%5E2+%2B+15x+%2B+9x%5E2%29+=+0\"
\n" ); document.write( "\"%28-2x+%2B+5%29%2A%2813x%5E2+%2B+25x+%2B+25%29+=+0\"
\n" ); document.write( "\"+-2x+%2B+5+=+0\" or \"13x%5E2+%2B+25x+%2B+25+=+0\"
\n" ); document.write( "Solve: \"-2x+%2B+5+=+0\"
\n" ); document.write( "\"highlight%28x+=+5%2F2%29\"
\n" ); document.write( "Solve: \"13x%5E2+%2B+25x+%2B+25+=+0\"
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"13x%5E2%2B25x%2B25+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2825%29%5E2-4%2A13%2A25=-675\".
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\n" ); document.write( " The discriminant -675 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -675 is + or - \"sqrt%28+675%29+=+25.9807621135332\".
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\n" ); document.write( " The solution is
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+13%2Ax%5E2%2B25%2Ax%2B25+%29\"

\n" ); document.write( "\n" ); document.write( "There is only one real solution, x = 5/2.
\n" ); document.write( "The other two roots are imaginary numbers as computed above.
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