document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=632190>Question 632190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose that y=5x-3 and that the value of x is increased by 3. what is the change in the value of y?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #398102 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=398102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "y = 5x - 3\r<BR>\n" );
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document.write( "replace x with (x+3), plug back in:\r<BR>\n" );
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document.write( "y = 5(x+3)    -3\r<BR>\n" );
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document.write( "y = 5x + 15   -3\r<BR>\n" );
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document.write( "y = 5x + 12\r<BR>\n" );
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document.write( "y has increased by a net change of 15 overall, say if x was originally zero, y would have gone from -3 to 12, a net change of +15\r<BR>\n" );
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