document.write( "Question 632073: Hospitals use radioactive substance iodine-131 in their researches.A hospital purchased 40 grams of the substance.Eight days later,when a doctor wanted to use some of the iodine-131,he found out that only 20 grams remained.Predict the amount remaining two weeks after purchase. \n" ); document.write( "
Algebra.Com's Answer #398004 by nerdybill(7384) You can put this solution on YOUR website! Hospitals use radioactive substance iodine-131 in their researches.A hospital purchased 40 grams of the substance.Eight days later,when a doctor wanted to use some of the iodine-131,he found out that only 20 grams remained.Predict the amount remaining two weeks after purchase. \n" ); document.write( "A = Pe^(kt) \n" ); document.write( "determine exponential decay constant k: \n" ); document.write( "20 = 40e^(k*8) \n" ); document.write( ".5 = e^(k*8) \n" ); document.write( "ln(.5) = k*8 \n" ); document.write( "ln(.5)/8 = k \n" ); document.write( ". \n" ); document.write( "Our equation is now: \n" ); document.write( "A = 40e^(t*ln(.5)/8) \n" ); document.write( ". \n" ); document.write( "Now we can answer:Predict the amount remaining two weeks after purchase. \n" ); document.write( "two weeks is equivalent to 14 days: \n" ); document.write( "thus t =14 \n" ); document.write( "A = 40e^(t*ln(.5)/8) \n" ); document.write( "A = 40e^(14*ln(.5)/8) \n" ); document.write( "A = 40e^(-1.213) \n" ); document.write( "A = 11.89 grams\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |