document.write( "Question 58198This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": Solve by completing the square\r
\n" ); document.write( "\n" ); document.write( "x^2 + 2 = 2x\r
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Algebra.Com's Answer #39798 by Earlsdon(6294)\"\" \"About 
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Solve by completing the square:
\n" ); document.write( "\"x%5E2+%2B+2+=+2x\" Subtact 2x from both sides.
\n" ); document.write( "\"x%5E2+-+2x+%2B+2+=+0\" Subtract 2 from both sides.
\n" ); document.write( "\"x%5E2+-+2x+=+-2\" Add the square of half the x-coefficient ((-2/2)^2 = 1) to both sides.
\n" ); document.write( "\"x%5E2+-+2x+%2B+1+=+-1\" Factor the left side.
\n" ); document.write( "\"%28x-1%29%5E2+=+-1\" Take the square root of both sides.
\n" ); document.write( "\"x-1+\"= +/-\"sqrt%28-1%29\" Add 1 to both sides.
\n" ); document.write( "\"x+=+1%2Bsqrt%28-1%29\" and \"x+=+1-sqrt%28-1%29\" which you can write as:
\n" ); document.write( "\"x+=+1%2Bi\" and \"x+=+1-i\" Where: \"i+=+sqrt%28-1%29\"
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