document.write( "Question 631807: A squirrel is running along a branch 144 feet above ground dislodges a pine cone. After how many seconds does the pine cone land on the ground? (assume no branches interfere with its fall).\r
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Algebra.Com's Answer #397969 by KMST(5328)\"\" \"About 
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As the pine cone falls, its downwards velocity increases linearly (starting from zero) at an acceleration of 32 ft/s^2 (32 ft per second every second).
\n" ); document.write( "In general, acceleration is represented by the letter \"a\".
\n" ); document.write( "(The acceleration due to gravity on the surface of planet Earth is often represented by the letter \"g\", and we know it is \"g=3.2\"\"ft%2Fs%5E2\").
\n" ); document.write( "The distance \"d\" traveled by an object starting at rest and accelerating at a constant acceleration \"a\" for a time \"t\" is given by
\n" ); document.write( "\"d=at%5E2%2F2\"
\n" ); document.write( "In this case, \"d=gt%5E2%2F2\"
\n" ); document.write( "We know \"d=144\" \"feet\", we know \"g=3.2\"\"ft%2Fs%5E2\"), and we want to know \"t\" , which we will get in seconds.
\n" ); document.write( "We can substitute first to get
\n" ); document.write( "\"144=32t%5E2%2F2\" and then solve.
\n" ); document.write( "\"144=32t%5E2%2F2\" --> \"144%2A2=32t%5E2\" --> \"144%2A2%2F32=t%5E2\" --> \"9=t%5E2\"
\n" ); document.write( "The solution that makes sense (we do not expect a negative time) is
\n" ); document.write( "\"t=sqrt%289%29\" --> \"t=3\" --> \"highlight%28t=3%29\" seconds.
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